0=(2-1.5*10^-9)+3x-x^2

Solution for 0=(2-1.5*10^-9)+3x-x^2 equation:

0=(2-1.5*10^-9)+3x-x^2

We move all terms to the left:

0-((2-1.5*10^-9)+3x-x^2)=0

We add all the numbers together, and all the variables

-((2-1.5*10^-9)+3x-x^2)=0


We calculate terms in parentheses: -((2-1.5*10^-9)+3x-x^2), so:

(2-1.5*10^-9)+3x-x^2

determiningTheFunctionDomain
-x^2+3x+(2-1.5*10^-9)

We add all the numbers together, and all the variables

-1x^2+3x+1.9999999985

Back to the equation:

-(-1x^2+3x+1.9999999985)


We get rid of parentheses

1x^2-3x-1.9999999985=0

We add all the numbers together, and all the variables

x^2-3x-1.9999999985=0

a = 1; b = -3; c = -1.9999999985;
Δ = b2-4ac
Δ = -32-4·1·(-1.9999999985)
Δ = 16.999999994
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{16.999999994}}{2*1}=\frac{3-\sqrt{16.999999994}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{16.999999994}}{2*1}=\frac{3+\sqrt{16.999999994}}{2}
$